Problems on Clocks and Calendars | How to Solve IBPS, SBI, SSC Reasoning Calendars Questions

By | January 4, 2020

Problems on Clocks and Calendars | How to Solve IBPS, SBI, SSC Reasoning Calendars Questions, लॉजिकल रीजनिंग घड़ी और कैलेंडर प्रश्न हिंदी में,  Reasoning Quiz questions on ‘Clocks and Calendars’ for Bank and SSC Exam,  Important points on Clock and Calendar reasoning questions

Important Formula and Equations

To ace questions based on clock, always remember these three basic rules.

  • The Hour hand of the clock rotates by 1/2 degree per minute
  • The Minute hand of the clock rotates by 6 degrees per minute
  • The Minute hand of the clock rotates 6 – 1/2 = 11/2 degrees with respect to the hour hand
  • Angle between minute hand and hour hand A = mod 30(H) – 11/2 (M) where, H and M are given hours and minutes

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Problems on Clocks and Calendars Question Answer for Bank, SSC Exam

1) Reasoning – Clocks – Basic Model Questions

Question 1) initially the clock showed 1:30 p.m., what will the time be after 1, 44,356 minutes?

Solution:

Important points on Clock and Calendar

Initial time given is 1:30 PM

The clock will show 1:30 PM again after 24 hours

24 hours = 24 X 60 minutes = 1440 minutes

After 1, 44,000 minutes, time will be 1:30 PM, since 1, 44,000 minutes = 1440 X 100

The question is, time after 1, 44,356 minutes

→ Time after 356 minutes → time after 5 hours 56 minutes → 7:26 PM

Question 2) In 8.5 hours, the hour hand rotates through __ degrees?

Solution:

First thing to do here is convert hours into minutes.

8 and half hours → 510 minutes

In 1 minute → 1/2 degrees rotation

In 510 minutes → 510/2 degrees → 255 degrees

Minute Spaces: The face or dial of watch is a circle whose circumference is divided into 60 equal parts, called minute spaces.

Hour Hand and Minute Hand: A clock has two hands, the smaller one is called the hour hand or short hand while the larger one is called minute hand or long hand .

In 60 minutes, the minute hand gains 55 minutes on the hour on the hour hand.

In every hour, both the hands coincide once.

The hands are in the same straight line when they are coincident or opposite to each other.

When the two hands are at right angles, they are 15 minute spaces apart.

When the hands are in opposite directions, they are 30 minute spaces apart.

घडी की सुई 12 घंटे में 360 ° का कोण बनाती है

घडी में मिनट की सुई 60 मिनट में 360 ° का कोण बनाती है

यदि घड़ी या घड़ी 8.15 इंगित करती है, जब सही समय 8 होता है, तो यह 15 मिनट बहुत तेज़ कहा जाता है।

दूसरी तरफ, यदि यह 7.45 इंगित करता है, जब सही समय 8 होता है, तो यह 15 मिनट बहुत धीमा कहा जाता है।

Odd Days: We are supposed to find the day of the week on a given date. For this, we use the concept of ‘odd days’. In a given period, the number of days more than the complete weeks are called odd days .

Leap Year: (i). Every year divisible by 4 is a leap year, if it is not a century. (ii). Every 4th century is a leap year and no other century is a leap year.

सामान्य वर्ष: वह वर्ष जो लीप वर्ष नहीं है उसे सामान्य वर्ष कहा जाता है। एक साधारण वर्ष में 365 दिन होते हैं।

Counting of Odd Days: 1 ordinary year = 365 days = (52 weeks + 1 day.) . 1 ordinary year has 1 odd day.

1 लीप वर्ष = 366 दिन = (52 सप्ताह + 2 दिन) 1 लीप वर्ष में 2 ओड दिन हैं।

100 साल = 76 साधारण वर्ष + 24 लीप साल

               = (76 x 1 + 24 x 2) odd days = 124 odd days.

               = (17 weeks + days) = 5 odd days.

100 वर्षों में ओड दिनों की संख्या = 5

200 वर्षों में विषम दिनों की संख्या = (5 x 2) = 3 विषम दिन।

300 वर्षों में विषम दिनों की संख्या = (5 x 3) = 1 विषम दिन।

400 वर्षों में विषम दिनों की संख्या = (5 x 4 + 1) = 0 विषम दिन

Similarly, each one of 800 years, 1200 years, 1600 years, 2000 years etc. has 0 odd days.

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Day of the Week Related to Odd Days (Assuming that 1AD January 1st is a Sunday)

लॉजिकल रीजनिंग घड़ी और कैलेंडर प्रश्न हिंदी में

मुख्य नोट्स:

घड़ियों की अवधारणा

घड़ी का डायल आकार में परिपत्र है और 60 बराबर मिनट की जगहों में बांटा गया\

60 minute spaces traces an angle of 360. Therefore, 1minute space traverses an angle of 60

The hands of clock are perpendicular in 15 minute spaces apart

The hands of clock are in straight line and opposite to each other in 30 minute spaces apart.

The hands of clock are in straight line when they coincide or opposite to each other.

The hands of clock are perpendicular to each other for 22 times in 12 hours and for 44 times in a day.

The hands of clock are opposite to each other for 11 times in 12 hours and 22 times in a day.

The hands of clock coincides with each other for 11 times in 12 hours and 22 times per day

Hence x minute space to be gained by minute hand over hour hand can be calculated as x.(60/55) or x.(12/11)

Ex : At what time between 2’O clock and 3’O clock the hands of the clock

are opposite to each other.

  1. 34(6/11) past 2’Oclock 2. 43 (7/11) past 2’Oclock
  2. 56(8/11) past 2’Oclock 4. 64 (9/11past 2’Oclock

Sol At 2’O clock the minute hand will be at 12 as shown below

Reasoning – Calendars – Advanced Model Questions

Question 11) the year after 1990 which has same calendar as that of 1990 is ____?

Solution:

Assume that 1 Jan 1990 is Sunday. Divide 365 by 7, the remainder is 1. So, 1 odd day per year

  • 1991 → 1 odd day → Monday
  • 1992 → 2 odd day’s → Tuesday
  • 1993 → 4 odd days (1992 is a leap year) → Thursday
  • 1994 → 5 odd days – Friday
  • 1995 → 6 odd days – Saturday
  • 1996 → 7 odd days – Sunday
  • So, same calendar will again be repeated in 1996. Keep in mind that leap year has 2 odd days

Question: – It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

  • Sunday
  • Saturday
  • Friday
  • Wednesday

Answer: Option C

Explanation

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

 On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday

What was the day of the week on 28th May, 2006?
·         Thursday

·         Friday

·         Saturday

·         Sunday

Answer: Option D

Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2)  6 odd days

Jan.  Feb.   March    April    May

(31 +  28  +  31   +   30   +   28 ) = 148 days

148 days = (21 weeks + 1 day)  1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7  0 odd day.

Given day is Sunday.

Reasoning Ability Syllabus for Bank Exam 2018

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